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 A125169 16n+15. 8
 15, 31, 47, 63, 79, 95, 111, 127, 143, 159, 175, 191, 207, 223, 239, 255, 271, 287, 303, 319, 335, 351, 367, 383, 399, 415, 431, 447, 463, 479, 495, 511, 527, 543, 559, 575, 591, 607, 623, 639, 655, 671, 687, 703, 719, 735, 751, 767, 783, 799, 815, 831, 847 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 COMMENTS The identity (16*n+15)^2-(16*(n+1)^2-2*(n+1))*4^2=1 can be written as a(n)^2-A158058(n+1)*4^2=1. - Vincenzo Librandi, Feb 01 2012 a(n-3), n>=3, appears in the third column of triangle A239126 related to the Collatz problem. Wolfdieter Lang, Mar 14 2014 LINKS Vincenzo Librandi, Table of n, a(n) for n = 0..10000 Tanya Khovanova, Recursive Sequences E. J. Barbeau, Polynomial Excursions, Chapter 10: Diophantine equations (2010), pages 84-85 (row 15 in the first table at p. 85, case d(t) = t*(4^2*t-2)). Index entries for linear recurrences with constant coefficients, signature (2,-1). FORMULA a(0)=15, a(1)=31, a(n)=2*a(n-1)-a(n-2). - Harvey P. Dale, Jan 03 2012 O.g.f: (15 + x)/(1 - x)^2. Wolfdieter Lang, Mar 14 2014 MATHEMATICA Table[16n + 15, {n, 0, 100}] LinearRecurrence[{2, -1}, {15, 31}, 100] (* or *) Range[15, 1620, 16] (* Harvey P. Dale, Jan 03 2012 *) PROG Contribution by Vincenzo Librandi, Jan 04 2012: (Start) (MAGMA) I:=[15, 31]; [n le 2 select I[n] else 2*Self(n-1)-Self(n-2): n in [1..60]]; (PARI) a(n) = 16*n + 15. (End) CROSSREFS Cf. A158058. Sequence in context: A031467 A045063 A044076 * A044457 A249452 A132757 Adjacent sequences:  A125166 A125167 A125168 * A125170 A125171 A125172 KEYWORD nonn,easy,changed AUTHOR Artur Jasinski, Nov 22 2006 STATUS approved

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Last modified June 28 11:33 EDT 2017. Contains 288820 sequences.