OFFSET
0,2
COMMENTS
Conjecture - requires proof.
FORMULA
a(n)=4^A122247(n); a(n)=4^sum{k=1..n, sum{j=0..n, floor(k/2^j)}};
MATHEMATICA
Table[4^(Sum[Sum[Floor[k/2^j], {j, 0, n}], {k, n}]), {n, 0, 10}] (* James C. McMahon, Oct 27 2024 *)
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Aug 27 2006
EXTENSIONS
a(10) from James C. McMahon, Oct 27 2024
STATUS
approved