login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A120879
G.f. satisfies: A(x) = A(x^3)*(1 + 3*x + 2*x^2).
1
1, 3, 2, 3, 9, 6, 2, 6, 4, 3, 9, 6, 9, 27, 18, 6, 18, 12, 2, 6, 4, 6, 18, 12, 4, 12, 8, 3, 9, 6, 9, 27, 18, 6, 18, 12, 9, 27, 18, 27, 81, 54, 18, 54, 36, 6, 18, 12, 18, 54, 36, 12, 36, 24, 2, 6, 4, 6, 18, 12, 4, 12, 8, 6, 18, 12, 18, 54, 36, 12, 36, 24, 4, 12, 8, 12, 36, 24, 8, 24, 16, 3, 9
OFFSET
0,2
COMMENTS
a(n) = 3^A062756(n) * 2^A081603(n), where A062756(n) is the number of 1's and A081603(n) is the number of 2's, in the ternary expansion of n.
More generally, if g.f. of {a(n)} satisfies: A(x) = A(x^d)*(1+Sum_{k=1..d-1} c(k)*x^k), then a(n) = Product_{k=1..d-1} c(k)^digits(n,k,d), where digits(n,k,d) is the number of k's in the d-ary expansion of n and d is any integer > 1. This sequence is a simple example for d=3 with c(1)=3 and c(2)=2.
LINKS
FORMULA
G.f.: A(x) = Product_{n>=0} (1 + x^(3^n))*(1 + 2*x^(3^n)).
a(n) = a(floor(n/3)) * 3^((n mod 3) mod 2) * 2^floor((n mod 3)/2) with a(0)=1.
PROG
(PARI) {a(n)=local(A=1+x+x*O(x^n)); for(i=1, floor(log(n+1)/log(3))+1, A=subst(A, x, x^3+x*O(x^n))*(1+3*x+2*x^2)); polcoeff(A, n, x)}
(PARI) /* Recurrence: */ {a(n)=if(n==0, 1, a(n\3)*3^((n%3)%2)*2^((n%3)\2))}
CROSSREFS
KEYWORD
nonn,look
AUTHOR
Paul D. Hanna, Jul 11 2006
STATUS
approved