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%I #5 Mar 30 2012 18:36:04
%S 1,3,8,15,71,105,886,1155,12673,15015,255802,285285,18447227,20255235,
%T 1366902806,1478632155,109463953829,116811940245,15332301522476,
%U 16236859694055,6624458815881211,6998086528137705,2875388753804702068
%N Sequence of pairs numerator(s(n)), denominator(s(n)) where s(n) is the n-th partial sum of 1/A119753(n).
%C There are only 66 terms of A119753 known and s(66) is 0.95578109643864566820083634846514203365246166270989 to 50 decimal places. What is sum(1/A119753(k),k=1..infinity)?
%F a(2n-1) = numerator(s(n)), a(2n)=denominator(s(n)), where s(n)=sum(1/A119753(k),k=1..n).
%e a(5)=71, a(6)=105 since s(3)=1/3+1/5+1/7=71/105.
%Y Cf. A119751, A119753.
%K nonn
%O 1,2
%A _Walter Kehowski_, Jun 23 2006
%E This is not really a sequence. The standard OEIS convention would be to split this into two cross-referenced sequences with keyword "frac". - _N. J. A. Sloane_, Jul 22 2006
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