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A119564
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Define F(n) = 2^(2^n)+1 = n-th Fermat number, M(n) = 2^n-1 = the n-th Mersenne number. Then a(n) = F(n)-M(n)-1 = 2^(2^n) - 2^n + 1.
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2
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2, 3, 13, 249, 65521, 4294967265, 18446744073709551553, 340282366920938463463374607431768211329, 115792089237316195423570985008687907853269984665640564039457584007913129639681
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OFFSET
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0,1
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LINKS
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EXAMPLE
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F(2) = 2^(2^2)+1 = 17, M(2) = 2^2-1 = 3, F(2)-M(2)-1 = 13.
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PROG
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(PARI) fm4(n) = for(x=0, n, y=2^(2^x)+1-(2^x-1)-1; print1(y", "))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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