%I #31 Jul 21 2022 03:06:46
%S 1,2,1,6,5,2,14,22,18,6,34,85,118,84,24,82,311,660,780,480,120,198,
%T 1100,3380,5964,6024,3240,720,478,3809,16380,40740,60480,52920,25200,
%U 5040,1154,13005,76518,258804,531864,676080,519840,221760,40320,2786,43978,348462,1564314,4286880,7444800,8240400
%N Triangle read by rows: rows = inverse binomial transforms of columns of A309220.
%C First few columns of A309220:
%C 1, 2, 6, 14, 34, ...
%C 1, 3, 11, 36, 119, ...
%C 1, 4, 18, 76, 322, ...
%C 1, 5, 27, 140, 727, ...
%C 1, 6, 38, 234, 1442, ...
%C 1, 7, 51, 364, 2599, ...
%C 1, 8, 66, 536, 4354, ...
%C ...
%e First few rows of the triangle:
%e 1;
%e 2, 1;
%e 6, 5, 2;
%e 14, 22, 18, 6;
%e 34, 85, 118, 84, 24;
%e 82, 311, 660, 780, 480, 120;
%e ...
%e Column 3 of A309220 = (6, 11, 18, 27, 38, 51, ...), whose inverse binomial transform is (6, 5, 2).
%p with(transforms);
%p M := 12;
%p T := [1];
%p S := series((1 + x^2)/(1-x-x^2 + x*y), x, 120):
%p for n from 1 to M do
%p R2 := expand(coeff(S, x, n));
%p R3 := [seq(abs(coeff(R2,y,n-i)),i=0..n)];
%p f := k-> add( R3[i]*k^(n-i+1), i=1..nops(R3) ):
%p s1 := [seq(f(i),i=1..3*n)];
%p s2 := BINOMIALi(s1);
%p s3 := [seq(s2[i],i=1..n+1)];
%p T := [op(T), op(s3)];
%p od:
%p T; # _N. J. A. Sloane_, Aug 12 2019
%Y The leading column is A099425, and the rightmost two diagonals are A038720 and A000142.
%Y Cf. A104509, A117938, A118981, A309220.
%K nonn,tabl
%O 1,2
%A _Gary W. Adamson_, May 07 2006
%E Edited and extended by _N. J. A. Sloane_, Aug 12 2019, guided by the comments of _R. J. Mathar_ from Oct 30 2011