|
|
A118436
|
|
Column 0 of triangle A118435.
|
|
3
|
|
|
1, 1, -3, -11, 25, 41, -43, 29, -335, -1199, 3117, 6469, -10295, -8839, -16123, -108691, 354145, 873121, -1721763, -2521451, 1476985, -6699319, 34182197, 103232189, -242017775, -451910159, 597551757, 130656229, 2465133865, 10513816601, -29729597083, -66349305331
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,3
|
|
COMMENTS
|
Binomial transform of A118434 = (1, 1, 3, 11, 25, 41, 43, -29, -335, -1199, ...). - Gary W. Adamson, Sep 19 2008
|
|
LINKS
|
|
|
FORMULA
|
G.f.: (1 + x + 2*x^2 - 6*x^3 + 29*x^4 + 5*x^5)/((1-x^2)*(1 + 6*x^2 + 25*x^4)).
|
|
MATHEMATICA
|
LinearRecurrence[{0, -5, 0, -19, 0, 25}, {1, 1, -3, -11, 25, 41}, 32] (* Jean-François Alcover, Apr 08 2024 *)
|
|
PROG
|
(PARI) {a(n)=polcoeff((1+x+2*x^2-6*x^3+29*x^4+5*x^5)/(1-x^2)/(1+6*x^2+25*x^4+x*O(x^n)), n)}
|
|
CROSSREFS
|
|
|
KEYWORD
|
sign
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|