A117707 Largest number of previous terms having at least one common digit in decimal representation.

0, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 20, 20, 20, 20, 20, 20, 20, 20, 20, 20, 21, 21, 22, 22

Offset

0,4

Comments

a(n) = A003056(n) for n <= 63.

Links

Table of n, a(n) for n=0..87.

Example

n=64: occurrences of digit d in the first 63 terms:
d=0:#{a(0),a(55),a(56),a(57),a(58),a(59),a(60),a(61),a(62),a(63)}=10,
d=1:#{a(1),a(2),a(55),a(56),a(57),a(58),a(59),a(60),a(61),a(62),a(63)}=11,
d=2:#{a(3),a(4),a(5)}=3,
d=3:#{a(6),a(7),a(8),a(9)}=4,
d=4:#{a(10),a(11),a(12),a(13),a(14)}=5,
d=5:#{a(15),a(16),a(17),a(18),a(19),a(20)}=6,
d=6:#{a(21),a(22),a(23),a(24),a(25),a(26),a(27)}=7,
d=7:#{a(28),a(29),a(30),a(31),a(32),a(33),a(34),a(35)}=8,
d=8:#{a(36),a(37),a(38),a(39),a(40),a(41),a(42),a(43),a(44)}=9,
d=9:#{a(45),a(46),a(47),a(48),a(49),a(50),a(51),a(52),a(53),a(54)}=10,
therefore a(64) = max{10, 11, 3, 4, 5, 6, 7, 8, 9, 10} = 11.

Crossrefs

Sequence in context: A169894 A357930 A003056 * A163352 A087834 A172263

Adjacent sequences: A117704 A117705 A117706 * A117708 A117709 A117710

Keyword

nonn,base

Author

Reinhard Zumkeller, Apr 13 2006

Status

approved