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A117608 Let p be an element of A110028, the set of all primes that have prime digits, a prime number of digits and whose digits sum to a prime. Let L(p) be the sorted list of digits of p and let LL be the set of all L(p) with duplicates removed and ordered lexicographically. Then a(n) is the first element of A110028 such that L(a(n))=LL(n). 0
23, 223, 227, 337, 353, 557, 577, 773, 22573, 23327, 25253, 27527, 32233, 33353, 33377, 35353, 35537, 53777, 57557, 75577, 77377 (list; graph; refs; listen; history; text; internal format)



Table of n, a(n) for n=1..21.


a(4)=337 since 337, 373 and 733 all have the same sorted list of digits [3,3,7].


a:=proc(b, n) local nn: nn:=convert(n, base, b): if isprime(n) and isprime(nops(nn)) and andmap(isprime, nn) and isprime(convert(nn, `+`)) then n else fi end: L:=[seq(a(10, k), k=1..10^5)]; U:=[]: for z to 1 do A:=L; for x in L do l:=sort(convert(x, base, 10)); m:=[selectremove(proc(z) sort(convert(z, base, 10))=l end, A)]; if not m[1]=[] then U:=[op(U), min(op(m[1]))]; fi; if m[2]=[] then break else A:=m[2]; fi od od; U;


Cf. A000040, A062088, A110028.

Sequence in context: A194783 A254870 A110028 * A038514 A244766 A125386

Adjacent sequences:  A117605 A117606 A117607 * A117609 A117610 A117611




Walter Kehowski, Apr 06 2006



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Last modified July 25 19:05 EDT 2021. Contains 346291 sequences. (Running on oeis4.)