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A116969 If n mod 2 = 0 then 3*2^(n-1)+n-1 else 3*2^(n-1)+n. 0

%I #11 Jun 13 2015 00:52:04

%S 4,7,15,27,53,101,199,391,777,1545,3083,6155,12301,24589,49167,98319,

%T 196625,393233,786451,1572883,3145749,6291477,12582935,25165847,

%U 50331673,100663321,201326619,402653211,805306397,1610612765,3221225503,6442450975,12884901921

%N If n mod 2 = 0 then 3*2^(n-1)+n-1 else 3*2^(n-1)+n.

%C Number of moves to solve Easy Pagoda puzzle.

%D Richard I. Hess, Compendium of Over 7000 Wire Puzzles, privately printed, 1991.

%D Richard I. Hess, Analysis of Ring Puzzles, booklet distributed at 13th International Puzzle Party, Amsterdam, Aug 20 1993.

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (3,-1,-3,2).

%F a(n) = 3*a(n-1)-a(n-2)-3*a(n-3)+2*a(n-4). G.f.: -x*(x^3-2*x^2-5*x+4) / ((x-1)^2*(x+1)*(2*x-1)). - _Colin Barker_, Jul 18 2013

%p f:=n-> if n mod 2 = 0 then 3*2^(n-1)+n-1 else 3*2^(n-1)+n; fi;

%t f[n_]:=If[EvenQ[n],3*2^(n-1)+n-1,3*2^(n-1)+n]; f/@Range[40] (* _Harvey P. Dale_, Sep 21 2012 *)

%K nonn,easy

%O 1,1

%A _N. J. A. Sloane_, Apr 01 2006

%E More terms from _Colin Barker_, Jul 18 2013

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Last modified May 10 07:40 EDT 2024. Contains 372358 sequences. (Running on oeis4.)