OFFSET
1,1
COMMENTS
If k+3 has d digits, the concatenation is k//k+3 = 10^d*k+k+3 = m*(m+2), therefore k//k+4 = 10^d*k+k+4 = (m+1)^2, so there is a large overlap with A115437. - R. J. Mathar, May 22 2026
CROSSREFS
KEYWORD
nonn,base,changed
AUTHOR
Giovanni Resta, Feb 06 2006
STATUS
approved
