A116122 Numbers k such that k concatenated with k-5 gives the product of two numbers which differ by 3.

92185, 1453156572932210152879253333913, 3829098407015032018435618903285, 1017438814759112270449904796121753809

Offset

1,1

Comments

If k-5 has d digits, the concatenation is k//k-5 = 10^d*k+k-5 = m*(m+3), therefore k//k-9 = 10^d*k+k-9 = (m-1)*(m+4), so there is a large overlap (or equality) with A116097. - R. J. Mathar, May 22 2026

Links

Table of n, a(n) for n=1..4.

Example

92185//92180 = 96012 * 96015, where // denotes concatenation.

Crossrefs

Cf. A116097, A116110, A116121, A054214, A116128, A116253.

Sequence in context: A330159 A202590 A116097 * A116134 A318631 A194722

Adjacent sequences: A116119 A116120 A116121 * A116123 A116124 A116125

Keyword

nonn,base

Author

Giovanni Resta, Feb 06 2006

Status

approved