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A115424
Integers n > 0 such that n XOR 62*n = 63*n.
6
1, 2, 4, 8, 16, 32, 64, 65, 128, 129, 130, 256, 257, 258, 260, 512, 513, 514, 516, 520, 1024, 1025, 1026, 1028, 1032, 1040, 2048, 2049, 2050, 2052, 2056, 2064, 2080, 4096, 4097, 4098, 4100, 4104, 4112, 4128, 4160, 4161, 8192, 8193, 8194, 8196, 8200, 8208
OFFSET
1,2
LINKS
FORMULA
This sequence also seems to satisfy:
3*a(n) XOR 41*a(n) = 42*a(n);
5*a(n) XOR 35*a(n) = 38*a(n);
6*a(n) XOR 35*a(n) = 37*a(n);
7*a(n) XOR 35*a(n) = 36*a(n); etc.
MATHEMATICA
Select[Range[8300], BitXor[#, 62 #]==63 #&] (* Harvey P. Dale, Oct 31 2021 *)
PROG
(Perl)
$cnt=0;
foreach(1..8_000){
print ++$cnt, " $_\n" if ((62*$_)^$_)==63*$_;
}
# Ivan Neretin, Nov 11 2016
(PARI) isok(n) = bitxor(n, 62*n) == 63*n; \\ Michel Marcus, Nov 11 2016
CROSSREFS
Cf. A003714 (Fibbinary numbers), A048715, A048718, A115422, A115423.
Sequence in context: A000855 A036135 A036131 * A372944 A381069 A225878
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Jan 22 2006
STATUS
approved