OFFSET
0,3
COMMENTS
a(2n) and a(2n+1) are both divisible by 2^n n! a(2n) = 2n a(2n-1) The number of pi in S_n such that maj pi is even and maj pi^(-1) is odd is exactly half of a(n)
LINKS
H. Barcelo, B. Sagan and S. Sundaram, Counting permutations by congruence class of major index, preprint, 2005.
H. Barcelo, B. Sagan and S. Sundaram, Counting permutations by congruence class of major index, Advances in Applied Mathematics, Volume 39, Issue 2, August 2007, Pages 269-281.
FORMULA
a(2n) = 2 n^2 a(2n-2) + 2 n (n-1) b(2n-2) and a(2n+1) = 2 n (n+1) a(2n-1) + 2 n^2 b(2n-1) where b(n) is sequence A113247
EXAMPLE
a(3)=2 because the following 2 permutations in S_3 have opposite parity for their major index and the major index of their inverse: 231, 312.
CROSSREFS
KEYWORD
nonn
AUTHOR
Bruce E. Sagan, Oct 20 2005
STATUS
approved