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A112845
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Recurrence a(n) = a(n-1)^3 - 3*a(n-1) with a(0) = 6.
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7
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OFFSET
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0,1
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COMMENTS
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Identical to A006243 apart from the initial term. For some general remarks on this recurrence see A001999. - Peter Bala, Nov 13 2012
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LINKS
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FORMULA
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a(n) = -2*cos(3^n*arccos(-3)).
a(n) = (3 + 2*sqrt(2))^(3^n) + (3 - 2*sqrt(2))^(3^n).
Product {n = 0..inf} (1 + 2/(a(n) - 1)) = sqrt(2).
(End)
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MATHEMATICA
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RecurrenceTable[{a[n] == a[n - 1]^3 - 3*a[n - 1], a[0] == 6}, a, {n,
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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