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A112726 First positive multiple of 3^n whose reverse is also a multiple of 3^n. 2
1, 3, 9, 999, 999999999, 4899999987, 19899999972, 28999899936, 49989892689, 49999917897, 68899199886, 68899199886, 68899199886, 2678052898989, 17902896898419, 137530987695297, 189281899170567, 368055404997498 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,2

COMMENTS

a(0)=1; a(1)=3 and it is easily shown that for n>1, 10^3^(n-2)-1 is a multiple of 3^n whose reverse is also a multiple of 3^n (see comments line of A062567), so for each n, a(n) exists and for n>1, a(n)<=10^3^(n-2)-1. This sequence is a subsequence of A062567, a(n)=A062567(3^n). Jud McCranie conjectures that for n>1, a(n)=10^3^(n-2)-1 (see comments line of A062567), but we see that for n>4, a(n) is much smaller than 10^3^(n-2)-1, so his conjecture is rejected. It seems that only for n=2,3 & 4 we have, a(n)=10^3^(n-2)-1.

LINKS

Table of n, a(n) for n=0..17.

EXAMPLE

a(20)=218264275944702783 because 218264275944702783=3^20*62597583

387207449572462812=3^20*111050012 & 218264275944702783 is the

smallest positive multiple of 3^20 whose reverse is also amultiple

of 3^20. I found a(n) for n<21, a(18) & a(19) are respectively

14048104419899757 & 171101619858478932.

MATHEMATICA

b[n_]:=(For[m=1, !IntegerQ[FromDigits[Reverse[IntegerDigits[m*n]]]/n], m++ ]; m*n); Do[Print[b[3^n]], {n, 0, 18}]

CROSSREFS

Cf. A062567, A112725.

Sequence in context: A069028 A318246 A137043 * A112725 A060712 A122463

Adjacent sequences: A112723 A112724 A112725 * A112727 A112728 A112729

KEYWORD

base,nonn

AUTHOR

Farideh Firoozbakht, Nov 13 2005

STATUS

approved

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Last modified November 27 13:54 EST 2022. Contains 358405 sequences. (Running on oeis4.)