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Inverse of renewal array for central trinomial numbers.
2

%I #4 Mar 30 2012 18:59:12

%S 1,-1,1,-1,-2,1,3,-1,-3,1,1,8,0,-4,1,-9,-3,14,2,-5,1,1,-26,-15,20,5,

%T -6,1,27,27,-45,-37,25,9,-7,1,-13,76,98,-56,-70,28,14,-8,1,-81,-135,

%U 108,228,-46,-114,28,20,-9,1,67,-202,-459,48,420,0,-168,24,27,-10,1,243,567,-135,-1035,-210,662,98,-230,15,35,-11,1,-285

%N Inverse of renewal array for central trinomial numbers.

%C Row sums have g.f. 1/sqrt(1+4x^2) [alternating sign central binomial numbers with interpolated zeros]. Diagonal sums are A111964. Inverse of A111960. Factors as (1/sqrt(1+4x^2),x/sqrt(1+4x^2))*(1/(1+x),x/(1+x)).

%F Riordan array (1/(sqrt(1+4x^2)+x), x/(sqrt(1+4x^2)+x)); Number triangle T(n, k)=sum{i=0..floor(n/2), C(2i+k-n-1, k)*C((2i-n-1)/2, i)(-1)^n*4^i}.

%e Triangle begins

%e 1;

%e -1,1;

%e -1,-2,1;

%e 3,-1,-3,1;

%e 1,8,0,-4,1;

%e -9,-3,14,2,-5,1;

%e 1,-26,-15,20,5,-6,1;

%K easy,sign,tabl

%O 0,5

%A _Paul Barry_, Aug 23 2005