

A111898


Number of numbers m <= n such that 8 equals the second digit after decimal point of square root of n in decimal representation.


11



0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 11, 11, 11, 11, 12, 12, 13, 13, 13, 13, 13
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OFFSET

1,29


COMMENTS

For n > 1: if A111862(n)=8 then a(n) = a(n1) + 1, otherwise a(n) = a(n1).
Lim_{n>infinity} a(n)/n = 1/10.


REFERENCES

G. Pólya and G. Szegő, Problems and Theorems in Analysis I (Springer 1924, reprinted 1972), Part Two, Chap. 4, Sect. 4, Problem 178.


LINKS



EXAMPLE

a(10) = 0, a(100) = 13, a(1000) = 94, a(10000) = 1002.


CROSSREFS



KEYWORD

nonn,base


AUTHOR



STATUS

approved



