That is, a(n) = Floor[ n*(n+1)...*(10^k-1)/R, where k is the number of digits in n and R = (n-1)(n-2)...(10^(k-1)+1}{10^(k-1))].
Comment from David Wasserman, Dec 01 2008: There is no room for the next term, which is
257182031095525112107857249934597388918419224714455526533820998388496472\
644482792132224051962512451185663850090463028434334174412800000000000000\
0000000.
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