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 A109901 a(n) = binomial(n^2, n*(n+1)/2). 2
 1, 1, 4, 84, 8008, 3268760, 5567902560, 39049918716424, 1118770292985239888, 130276394656770614583240, 61448471214136179596720592960, 117118180539414377821494470432491764, 900390992257782351906806257139068209113040, 27883369051325994219981405855549095749234579210080 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,3 COMMENTS 8*a(2*n+1)^4 = A182010(n) = number of potential group developed cocyclic Hadamard matrices over (the group) Z_{(2*n+1)^2} X Z^2_2 [Baliga, et al., p. 130]. - L. Edson Jeffery, Apr 10 2012 LINKS Andrew Howroyd, Table of n, a(n) for n = 0..50 A. Baliga and K. J. Horadam, Cocyclic Hadamard matrices over Z_t X Z^2_2, Australas. J. Combin. 11(1995), 123-134. FORMULA a(n) = C(n^2, n*(n+1)/2) = (n^2!)/((n(n+1)/2)!*(n(n-1)/2)!). a(n) = C(n^2, n*(n-1)/2). EXAMPLE a(6) = 36!/(21!*15!) = 5567902560. MAPLE seq(binomial(n^2, n*(n+1)/2), n=0..12); # Emeric Deutsch, Jul 16 2005 MATHEMATICA Table[Binomial[n^2, (n(n+1))/2], {n, 20}] (* Harvey P. Dale, Jun 04 2011 *) PROG (PARI) a(n)=binomial(n^2, n*(n+1)/2) CROSSREFS Cf. variants: A014062 (C(n^2,n*(n-1)), A135757 (C(n*(n+1),n*(n+1)/2)). Cf. A182010. Sequence in context: A012189 A012076 A173211 * A015018 A204245 A287248 Adjacent sequences: A109898 A109899 A109900 * A109902 A109903 A109904 KEYWORD easy,nonn AUTHOR Amarnath Murthy, Jul 14 2005 EXTENSIONS More terms from Emeric Deutsch, Jul 16 2005 Offset changed to 0 (with a(0)=1), and name changed slightly by Paul D. Hanna, Jun 24 2011 Terms a(12) and beyond from Andrew Howroyd, Nov 09 2019 STATUS approved

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Last modified March 31 05:47 EDT 2023. Contains 361634 sequences. (Running on oeis4.)