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%I #9 Jan 01 2018 21:23:58
%S 1,321,213445,278905249,610897146201,2023268287369681,
%T 9449986579423765453,59214605458489033180545,
%U 479530506556330198532943409,4875296429727384973283863144801
%N (2n)-th Legendre polynomial P_{2n}(x), evaluated at x = 2n-1. Here the Legendre polynomials are normalized so that P_{n}(1) = 1.
%H G. C. Greubel, <a href="/A105952/b105952.txt">Table of n, a(n) for n = 1..175</a>
%F a(n) ~ n^(2*n)*2^(4*n)/(exp(1)*sqrt(2*Pi*n)). - _Vaclav Kotesovec_, Jul 31 2013
%e P_{4}(x) = 35/8*x^4 - 15/4*x^2 + 3/8; evaluating at x=3 gives 321.
%p with(orthopoly,P); seq(P(2*n,2*n-1), n=1..12);
%t Table[LegendreP[2*n,2*n-1], {n, 1, 20}] (* _Vaclav Kotesovec_, Jul 31 2013 *)
%o (PARI) a(n)=pollegendre(2*n,2*n-1) \\ _Charles R Greathouse IV_, Mar 19 2017
%K easy,nonn
%O 1,2
%A Isabel C. Lugo (izzycat(AT)gmail.com), Apr 27 2005
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