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%I #3 Mar 30 2012 18:59:02
%S 1,9,89,991,9909,88991,899911,9999009,99990089,899910991,8899099911,
%T 99089999009,990999990091,8899999911009,89999999100089,
%U 999999990000991,9999999900009909,89999999100088991,889999991100899911
%N A bisection of A101678.
%F a(n)=sum{k=0..n, (-1)^A010060(2n-2k)*mod(binomial(2n-k, k), 2)10^k}.
%K easy,nonn
%O 0,2
%A _Paul Barry_, Dec 11 2004