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A099187
Let D(n) = n*(9*n^2-9*n+2)/2 then a(k+1) = D(a(k)) and a(0) = 1.
1
1, 20, 34220, 180318314012420, 26383476911029432816173777932463879690054620
OFFSET
1,2
LINKS
Hyun Kwang Kim, On Regular Polytope Numbers, Proc. Amer. Math. Soc., 131 (2003), 65-75.
FORMULA
Let D(n) = n*(9*n^2-9*n+2)/2 then a(k+1) = D(a(k)) and a(0) = 1.
MATHEMATICA
Dod[n_]:= n*(9*n^2-9*n+2)/2;
a[n_]:= If[n==0, Dod[1], If[n==1, Dod[2], Dod[a[n-1]]]];
Table[a[n], {n, 0, 4}] (* G. C. Greubel, Mar 22 2019 *)
PROG
(PARI) dod(n) = n*(9*n^2-9*n+2)/2;
a(n) = if (n==0, 1, if (n==1, dod(2), dod(a(n-1)))); \\ Michel Marcus, Dec 14 2015
CROSSREFS
Sequence in context: A060618 A369948 A064487 * A129041 A129040 A159370
KEYWORD
easy,nonn
AUTHOR
Jonathan Vos Post, Nov 15 2004
STATUS
approved