OFFSET
1,1
COMMENTS
This sequence consists of all integers of the form (prime(m)*prime(m+4)+36)/prime(m+2), for m>0, where prime(m) = A000040(m). Also note that the integers resulting from that rule equal prime(m+2), therefore a(n) also consists of all integers of the form sqrt[prime(m)*prime(m+4)+36]. - Richard R. Forberg, Jan 11 2016
LINKS
Eric Weisstein's World of Mathematics, Prime Triplet
EXAMPLE
CROSSREFS
KEYWORD
nonn
AUTHOR
Reinhard Zumkeller, Sep 07 2004
STATUS
approved