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A098239
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Numbers n such that n^3 differs from smallest k > n that makes n^6+1 divide k^6+1.
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1
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OFFSET
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1,2
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COMMENTS
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a(8) > 10^6.
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LINKS
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MATHEMATICA
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f[n_] := Block[{k = 1, m}, While[m = (k^6 + 1)/(n^6 + 1); m < 2 || !IntegerQ[m], k++ ]; n^3 - k]; Do[ If[ f[n] != 0, Print[n]], {n, 215}] (* Robert G. Wilson v, Sep 03 2004 *)
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CROSSREFS
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KEYWORD
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nonn,hard,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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