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%I #21 Oct 01 2021 10:24:47
%S 8,170,2242,2132,1294,976846,216566,9904144,25617930,408928520,
%T 25346031262,137031675878,89950978114
%N Period length of continued fraction for square root of A095372(n)=1+90*(-1+100^n)/99.
%p with(numtheory): [seq(nops(cfrac((1+90*(-1+100^k)/99)^(1/2), 'periodic', 'quotients')[2]), k=2..10)];
%t Do[Print[Length[Last[ContinuedFraction[(1+90*(-1+100^n)/99)^(1/2)]]]], {n, 1, 9}]
%Y Cf. A095372, A096485.
%K nonn,hard,more
%O 1,1
%A _Labos Elemer_, Jun 25 2004
%E a(10) from _Vaclav Kotesovec_, Aug 29 2019
%E a(11)-a(12) from _Chai Wah Wu_, Dec 07 2019
%E a(13) from _Chai Wah Wu_, Oct 01 2021