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A096287
Number of iterations of n -> n + (product of nonzero digits of n) needed for the trajectory of n to join the trajectory of A063108.
3
0, 0, 5, 0, 6, 4, 3, 0, 2, 5, 4, 3, 1, 2, 2, 0, 3, 1, 5, 1, 10, 0, 9, 2, 7, 0, 9, 4, 8, 8, 5, 1, 7, 4, 6, 2, 15, 0, 2, 4, 8, 6, 5, 3, 7, 3, 7, 4, 16, 5, 17, 1, 2, 1, 4, 16, 7, 14, 1, 2, 4, 0, 322, 3, 6, 1, 3, 1, 17, 2, 16, 16, 17, 0, 6, 2, 1, 15, 14, 3, 321, 14, 4, 1, 15, 15, 13, 2, 320, 12, 3, 6, 2, 16
OFFSET
1,3
COMMENTS
Loomis has verified that all n up to 1000000 eventually join the trajectory of A063108.
LINKS
P. A. Loomis, An Introduction to Digit Product Sequences, J. Rec. Math., 32 (2003-2004), 147-151.
P. A. Loomis, An Introduction to Digit Product Sequences, J. Rec. Math., 32 (2003-2004), 147-151. [Annotated archived copy]
EXAMPLE
a(3)=5 because the trajectory for 1 (Sequence A063108) starts
1->2->4->8->16->22->26->38->62->74...
and the sequence for 3 starts
3->6->12->14->18->26->38->62->74...
so the sequence beginning with 3 joins A063108 after 5 steps.
PROG
(C) See Link section.
CROSSREFS
Sequence in context: A159751 A190914 A153458 * A240243 A330864 A144483
KEYWORD
base,nonn
AUTHOR
Jason Earls, Jun 23 2004
STATUS
approved