OFFSET
1,2
COMMENTS
Conjecture: No term is zero.
LINKS
Andrew Howroyd, Table of n, a(n) for n = 1..190 (rows 1..19)
EXAMPLE
Triangle begins:
1;
3,2;
4,5,6;
7,9,10,8;
11,12,13,14,15;
16,17,18,19,21,20;
...
Terms a(7) to a(10) are 7,9,10,8 respectively, a permutation of 7,8,9 and 10, the next four numbers and 79108 is a multiple of 4.
The 4th row contains a permutation of 7, 8, 9 and 10, the four numbers up to and including T(4)=A000217(4)=10. The concatenations 78910, 78109 etc. are not multiples of 4, which leaves the concatenation 79108 as the only (and therefore minimal) candidate for the ordering of the numbers in the row.
Row 14 is (100, 101, 102, 103, 104, 105, 92, 93, 94, 95, 97, 98, 99, 96). This is the first case where the smallest multiple is not the lexically least permutation whose concatenation is a multiple of n. The lexically least permutation would be (92, 93, 94, 95, 96, 97, 98, 99, 100, 103, 101, 105, 102, 104). - Andrew Howroyd, Aug 09 2025
PROG
(PARI) \\ suitable up to row 19. Too slow on row 20, 40, 50.
row(n)={my(v=vecsort(vector(n, i, digits(binomial(n, 2)+i)))); forperm(n, u, my(m=fromdigits(concat(vector(n, i, v[u[i]])))); if(m%n==0, return( vector(n, i, fromdigits(v[u[i]])) ) ))} \\ Andrew Howroyd, Aug 09 2025
CROSSREFS
KEYWORD
AUTHOR
Amarnath Murthy, Jul 06 2004
EXTENSIONS
More terms from R. J. Mathar, Aug 03 2007
a(46) onwards from Andrew Howroyd, Aug 09 2025
STATUS
approved
