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A095712
Triangle of numbers obtained by reversing the first n digits of 1/e and juxtaposing.
0
0, 3, 0, 6, 3, 0, 7, 6, 3, 0, 8, 7, 6, 3, 0, 7, 8, 7, 6, 3, 0, 9, 7, 8, 7, 6, 3, 0, 4, 9, 7, 8, 7, 6, 3, 0, 4, 4, 9, 7, 8, 7, 6, 3, 0, 1, 4, 4, 9, 7, 8, 7, 6, 3, 0, 1, 1, 4, 4, 9, 7, 8, 7, 6, 3, 0, 7, 1, 1, 4, 4, 9, 7, 8, 7, 6, 3, 0, 1, 7, 1, 1, 4, 4, 9, 7, 8, 7, 6, 3, 0, 4, 1, 7, 1, 1, 4, 4, 9, 7, 8, 7, 6, 3, 0
OFFSET
1,2
EXAMPLE
Triangle begins:
0;
3,0;
6,3,0;
7,6,3,0;
8,7,6,3,0;
... (reverse order of 0; 0.3; 0.36; 0.367; 0.3678;...)
MATHEMATICA
Module[{nn=20, er}, er=Join[{0}, RealDigits[1/E, 10, nn][[1]]]; Table[Reverse[Take[er, n]], {n, nn+1}]]//Flatten (* Harvey P. Dale, Jun 19 2025 *)
PROG
(PARI) a(n)=if(n<1, 0, default(realprecision, n+2); floor(exp(-1)*10^(n-1))%10);
b(n)=1+binomial(1+floor(1/2+sqrt(2*n)), 2)-n;
for(n=1, 120, print1(a(b(n))", "))
CROSSREFS
Cf. A068985.
Sequence in context: A113062 A259659 A005889 * A382521 A085753 A120008
KEYWORD
base,easy,nonn,tabl
AUTHOR
Herman Jamke (hermanjamke(AT)fastmail.fm), Jul 07 2004
STATUS
approved