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A094802
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a(n) = smallest k such that all of 1 through n divides k!.
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1
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1, 2, 3, 4, 5, 5, 7, 7, 7, 7, 11, 11, 13, 13, 13, 13, 17, 17, 19, 19, 19, 19, 23, 23, 23, 23, 23, 23, 29, 29, 31, 31, 31, 31, 31, 31, 37, 37, 37, 37, 41, 41, 43, 43, 43, 43, 47, 47, 47, 47, 47, 47, 53, 53, 53, 53, 53, 53, 59, 59
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OFFSET
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1,2
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COMMENTS
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It is conjectured that after n=4 the sequence is prime for n prime or the previous prime for n not prime.
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LINKS
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EXAMPLE
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a(6)=5 as 5!=120 which is divisible by 1,2,3,4,5 and 6.
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MAPLE
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local k, nlcm ;
for k from 1 do
if modp(k!, nlcm) = 0 then
return k ;
end if;
end do:
end proc:
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MATHEMATICA
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a[n_] := Module[{k = 1}, While[True, If[AllTrue[Range[n], Divisible[k!, #]&], Return[k]]; k++]];
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PROG
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(PARI) { for (i=1, 60, x=1; for (j=1, i, xf=x!; if (xf%j!=0, x+=1; j=1)); print1(", "x)) }
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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