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A087779
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a(n)=prime(x) is the smallest prime such that 1+(2^(12n+9))*prime(x) is divisible by prime(x+1).
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0
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19, 43, 67, 31, 2087, 29, 31, 89, 6359, 31, 29, 19, 31, 199, 1429, 29, 229, 641, 31, 41, 29, 31, 19, 89, 31, 29, 41, 31, 29573, 38729, 29, 89, 389, 19, 43103, 29, 31, 67, 929, 31, 29, 38729, 31, 89, 19, 29, 146543, 41, 31, 1193, 29, 31, 5077, 53, 31, 19, 449, 31, 701
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OFFSET
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0,1
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LINKS
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FORMULA
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a(n)=Min{p[x]; Mod[1+[2^(12n+9)].p[x], p[x+1]]=0}; a(n)=A087985[2^(9+12n)]
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EXAMPLE
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n = 4: exponent = 4.12+9 = 57, 2^57 = 144115188075855872; a(4) = 2087 = p[315] because 1+144115188075855872.2087 = 300768397514311204865 = 2089.5.23.2593.14669.32914927 = p[316].m
Must a solution always exist? Difficult exponents are 193,253,...
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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