OFFSET
1,1
COMMENTS
reverse(a(n)) = A086949(n).
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..300
Index entries for linear recurrences with constant coefficients, signature (11,-10).
FORMULA
a(n) = 2*(10^n-3).
From Stefano Spezia, Dec 15 2022: (Start)
O.g.f.: 2*x*(7 + 20*x)/((1 - x)*(1 - 10*x)).
E.g.f.: 2*(2 - 3*exp(x) + exp(10*x)).
a(n) = 11*a(n-1) - 10*a(n-2) for n > 2. (End)
PROG
(Magma) [2*(10^n-3): n in [1..25] ]; // Vincenzo Librandi, Aug 22 2011
CROSSREFS
KEYWORD
nonn,base,easy
AUTHOR
Ray Chandler, Jul 24 2003
STATUS
approved