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A086252
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a(n) is the smallest k such that 2^k-1 has n primitive prime factors.
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2
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OFFSET
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1,1
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COMMENTS
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A prime factor of 2^n-1 is called primitive if it does not divide 2^r-1 for any r<n. Equivalently, p is a primitive prime factor of 2^n-1 if ord(2,p)=n. See A086251 for the number of primitive prime factors in 2^n-1.
No more terms < 673. (2^673-1 is the first that is not completely factored in the linked reference.) - David Wasserman, Feb 22 2005
2^1207-1 is now the first not completely factored number of the form 2^k-1. - Hugo Pfoertner, Aug 06 2019
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REFERENCES
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J. Brillhart et al., Factorizations of b^n +- 1. Contemporary Mathematics, Vol. 22, Amer. Math. Soc., Providence, RI, 3rd edition, 2002.
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LINKS
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EXAMPLE
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a(2) = 11 because 2^11-1 = 23*89, both 23 and 89 have order 11 and the numbers 2^r-1 have only 0 or 1 primitive prime factors.
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CROSSREFS
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KEYWORD
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hard,more,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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