OFFSET
0,2
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..300
FORMULA
a(n) ~ (4*exp(15-225/(2*n))+1) * n^n / 5. - Amiram Eldar, Feb 09 2026
MATHEMATICA
Unprotect[Power]; Power[0, 0]=1; Protect[Power]; a[n_]:=(4*(n+15)^n + n^n)/5; Array[a, 16, 0] (* Stefano Spezia, Sep 19 2025 *)
PROG
(Magma) [(4*(n+15)^n+n^n)/5: n in [0..25]]; // Vincenzo Librandi, Jun 29 2011
(PARI) a(n)= (4*(n+15)^n+n^n)/5 \\ Charles R Greathouse IV, Jun 29 2011
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Apr 24 2003
STATUS
approved
