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A082841
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a(n) = 4*a(n-1) - a(n-2) for n>1, a(0)=3, a(1)=9.
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11
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3, 9, 33, 123, 459, 1713, 6393, 23859, 89043, 332313, 1240209, 4628523, 17273883, 64467009, 240594153, 897909603, 3351044259, 12506267433, 46674025473, 174189834459, 650085312363, 2426151414993, 9054520347609, 33791929975443
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OFFSET
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0,1
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COMMENTS
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y-values in the solutions to 3*x^2+6 = y^2. - Sture Sjöstedt, Nov 25 2011
Positive values of x (or y) satisfying x^2 - 4*x*y + y^2 + 18 = 0. - Colin Barker, Feb 04 2014
Positive values of x (or y) satisfying x^2 - 14*x*y + y^2 + 288 = 0. - Colin Barker, Feb 16 2014
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LINKS
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FORMULA
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G.f.: (3 -6*x +3*x^2)/((1-x)*(1-4*x+x^2)).
a(n) = sqrt(3/2)*(a^(n+1/2) + b^(n+1/2)), with a=2+sqrt(3) and b=2-sqrt(3).
a(n) = sqrt((3/2)*(A003500(2n+1) +2)).
a(n) == 3 (mod 6).
a(n) = 3*x(n) + 3*y(n) for x(n)= A001075(n) and y(n) = A001353(n) the solutions to x^2 - 3*y^2 = 1. - Greg Dresden and his Math 222 Linear Algebra class, Oct 05 2022
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MAPLE
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a:=proc(n) option remember; if n=0 then 3 elif n=1 then 9 else 4*a(n-1)-a(n-2); fi; end: seq(a(n), n=0..40); # Wesley Ivan Hurt, Jan 21 2017
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MATHEMATICA
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CoefficientList[Series[(3-6x+3x^2)/((1-x)(1-4x+x^2)), {x, 0, 25}], x]
LinearRecurrence[{4, -1}, {3, 9}, 30] (* Harvey P. Dale, Aug 28 2019 *)
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PROG
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(PARI) my(x='x+O('x^30)); Vec((3-6*x+3*x^2)/((1-x)*(1-4*x+x^2))) \\ G. C. Greubel, Feb 25 2019
(Magma) m:=30; R<x>:=PowerSeriesRing(Integers(), m); Coefficients(R!( (3-6*x+3*x^2)/((1-x)*(1-4*x+x^2)) )); // G. C. Greubel, Feb 25 2019
(Sage) ((3-6*x+3*x^2)/((1-x)*(1-4*x+x^2))).series(x, 30).coefficients(x, sparse=False) # G. C. Greubel, Feb 25 2019
(GAP) a:=[3, 9];; for n in [3..30] do a[n]:=4*a[n-1]-a[n-2]; od; a; # G. C. Greubel, Feb 25 2019
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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Mario Catalani (mario.catalani(AT)unito.it), Apr 14 2003
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STATUS
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approved
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