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A081837
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Let z(n) be e = exp(1.0) = 2.7182.... truncated to n decimal digits after the decimal point; sequence gives maximum element in the continued fraction for z(n).
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3
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2, 3, 4, 12, 9, 10, 12, 11, 9, 10, 8, 22, 13, 13, 15, 12, 35, 30, 48, 18, 166, 166, 68, 40, 73, 137, 57, 1288, 62, 28, 416, 552, 138, 47, 24, 156, 110, 31, 463, 85, 108, 106, 295, 295, 54, 98, 40, 388, 216, 32, 49, 199, 488, 47, 64, 822, 51, 152, 854, 38, 701, 88, 94, 149
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OFFSET
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0,1
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LINKS
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EXAMPLE
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... Here is Maple's computation of the first four terms of the sequence a:
....C2 := 2
....cf := [2]
....a := [2]
..........27
....C2 := --
..........10
....cf := [2, 1, 2, 3]
....a := [2, 3]
..........271
....C2 := ---
..........100
....cf := [2, 1, 2, 2, 4, 3]
....a := [2, 3, 4]
..........1359
....C2 := ----
..........500
....cf := [2, 1, 2, 1, 1, 4, 1, 12]
....a := [2, 3, 4, 12]
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MAPLE
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with(numtheory); Digits:=200:
C1 := exp(1.0);
for n from 1 to 100 do
C2:= floor(C1*10^(n-1))/10^(n-1);
cf := convert(evalf(C2), confrac):
a := [op(a), max(cf)];
od:
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MATHEMATICA
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A081837[n_] := Max[ContinuedFraction[Floor[E*10^n]/10^n]];
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CROSSREFS
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KEYWORD
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base,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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