OFFSET
1,1
COMMENTS
If n>3 is in the sequence so are 2n-1 and 2n+1.
FORMULA
a(n) = 2^floor(log[2](4*(n-1)))+2*n-1 for n>1, a(1)=3. - Antonio G. Astudillo (afg_astudillo(AT)hotmail.com), Feb 22 2003
Equals 2 * A004760(n) + 1. - Ralf Stephan, Sep 16 2003
CROSSREFS
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Feb 22 2003
STATUS
approved