OFFSET
1,1
COMMENTS
Equivalently, primes p such that p, p+6, p+12, p+16 and p+22 are consecutive primes.
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000 (terms 1..1000 from Harvey P. Dale)
FORMULA
EXAMPLE
151 is in the sequence since 151, 157 = 151 + 6, 163 = 151 + 12, 167 = 151 + 16 and 173 = 151 + 22 are consecutive primes.
MATHEMATICA
Transpose[Select[Partition[Prime[Range[30000]], 5, 1], Differences[#] == {6, 6, 4, 6}&]][[1]] (* Harvey P. Dale, Apr 06 2012 *)
PROG
(PARI) list(lim) = {my(p1 = 2, p2 = 3, p3 = 5, p4 = 7); forprime(p5 = 11, lim, if(p2 - p1 == 6 && p3 - p2 == 6 && p4 - p3 == 4 && p5 - p4 == 6, print1(p1, ", ")); p1 = p2; p2 = p3; p3 = p4; p4 = p5); } \\ Amiram Eldar, Feb 22 2025
CROSSREFS
KEYWORD
nonn
AUTHOR
Labos Elemer, Dec 19 2002
EXTENSIONS
Edited by Dean Hickerson, Dec 20 2002
STATUS
approved