OFFSET
1,3
COMMENTS
Appears to always be an integer. Next term is too large to include.
FORMULA
a(n) = (2^n-1-A000367(2^n))/2^n
MATHEMATICA
Table[(2^n-1-Numerator[BernoulliB[2^(n+1)]])/2^n, {n, 6}] (* Harvey P. Dale, Nov 16 2024 *)
PROG
(PARI) a(n)=(2^n-1-numerator(bernfrac((2^(n+1)))))/2^n
CROSSREFS
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Oct 19 2002
STATUS
approved