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 A076154 Let c=sum_{k>=0} 1/2^(k!), sequence gives values of terms congruent to 5 of the continued fraction for c. 2
 4095, 4722366482869645213695, 4095, 3121748550315992231381597229793166305748598142664971150859156959625371738819765620120306103063491971159826931121406622895447975679288285306290175, 4095, 4722366482869645213695, 4095 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS Observation: if b(k) denotes the sequence of all elements of the continued fraction for c, b(k)=4095 if k==6 or 19 (mod 24); b(k)=4722366482869645213695 if k==12 or 37 (mod 48) ... LINKS FORMULA It seems that for n>=1, a(2n-1)=4095; a(4n-2)=4722366482869645213695 etc. EXAMPLE The continued fraction for c is shown in A076157. The "big terms" are all congruent to 5. CROSSREFS Cf. A076152, A076157, A076187. Sequence in context: A069413 A069439 A212935 * A182685 A182686 A176768 Adjacent sequences:  A076151 A076152 A076153 * A076155 A076156 A076157 KEYWORD nonn,cofr AUTHOR Benoit Cloitre, Nov 02 2002 STATUS approved

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Last modified June 17 23:41 EDT 2021. Contains 345088 sequences. (Running on oeis4.)