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A074983
Successive factors of the Fibonacci word A003842.
0
12, 11212, 1121121211212, 1121121211211212112121121121211212, 11211212112112121121211211212112112121121211211212112121121121211211212112121121121211212
OFFSET
1,1
COMMENTS
a(6) is 233 digits long. - Sean A. Irvine, Oct 31 2011
REFERENCES
G. Melançon, Lyndon factorization of infinite words, STACS 96 (Grenoble, 1996), 147-154, Lecture Notes in Comput. Sci., 1046, Springer, Berlin, 1996. Math. Rev. 98h:68188.
FORMULA
Let b(1)=112, b(2)=12, a(1)=12. If a(n)=c(1)c(2)...c(m), then a(n+1)=b(c(1))b(c(2))...b(c(m)), where c(i) is the i-th digit of a(n). - Sean A. Irvine, Oct 31 2011
CROSSREFS
Sequence in context: A012732 A001322 A159411 * A381090 A159413 A317958
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, Mar 28 2003
EXTENSIONS
More terms from Sean A. Irvine, Oct 30 2011
STATUS
approved