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Least k > 1 such that k^n == 1 (mod n).
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%I #25 Feb 20 2024 07:01:51

%S 2,3,4,3,6,5,8,3,4,9,12,5,14,13,16,3,18,5,20,3,4,21,24,5,6,25,4,13,30,

%T 11,32,3,34,33,36,5,38,37,16,3,42,5,44,21,16,45,48,5,8,9,52,5,54,5,16,

%U 13,7,57,60,7,62,61,4,3,66,23,68,13,70,29,72,5,74,73,16,37,78,17,80,3

%N Least k > 1 such that k^n == 1 (mod n).

%H Rémy Sigrist, <a href="/A074792/b074792.txt">Table of n, a(n) for n = 1..10000</a>

%F If p is prime a(p)=p+1 and a(2p)=2p-1; if n is in A050384 a(n)=n+1; if n is in A067945 a(n)=3 etc. It seems that sum(k=1, n, a(k)) is asymptotic to c*n^2 with c=0.2...

%t Do[k = 2; While[ !IntegerQ[(k^n - 1)/n], k++ ]; Print[k], {n, 1, 80}] (* _Robert G. Wilson v_ *)

%o (PARI) a(n)=if(n<0,0,s=2; while((s^n-1)%n>0,s++); s)

%o (PARI) a(n)=my(s=2); while(Mod(s,n)^n-1!=0, s++); return(s) \\ _Rémy Sigrist_, Apr 02 2017

%Y a(n) = {A076944(n)}^(1/n).

%Y Cf. A076942, A076943, A076944.

%K nonn

%O 1,1

%A _Benoit Cloitre_, Sep 07 2002