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 A074139 Number of divisors of A036035(n,k). 19
 1, 2, 3, 4, 4, 6, 8, 5, 8, 9, 12, 16, 6, 10, 12, 16, 18, 24, 32, 7, 12, 15, 16, 20, 24, 27, 32, 36, 48, 64, 8, 14, 18, 20, 24, 30, 32, 36, 40, 48, 54, 64, 72, 96, 128, 9, 16, 21, 24, 25, 28, 36, 40, 45, 48, 48, 60, 64, 72, 81, 80, 96, 108, 128, 144, 192, 256 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,2 LINKS Alois P. Heinz, Rows n = 0..30, flattened Byungchul Cha et al., An Investigation on Partitions with Equal Products, arXiv:1811.07451 [math.NT], 2018. FORMULA T(n,k) = A000005(A036035(n,k)). - R. J. Mathar, Aug 28 2018 EXAMPLE Express A036035(n,k) by its prime signature; add one to each exponent, then multiply: 180 = (2^2)*(3^2)*(5^1) therefore the number of divisors is (2+1)*(2+1)*(1+1)= 18 From Michel Marcus, Nov 11 2015: (Start) As an irregular triangle, whose n-th row has A000041(n) terms, sequence begins:   1;   2;   3,  4;   4,  6,  8;   5,  8,  9, 12, 16;   6, 10, 12, 16, 18, 24, 32;   ... (End) PROG (PARI) tabf(nn) = {for (n=1, nn, forpart(p=n, print1(prod(k=1, #p, (1+p[k])), ", ")); print(); ); } \\ Michel Marcus, Nov 11 2015 CROSSREFS Row sums give A074141. Cf. A036035, A074140. Sequence in context: A351006 A325682 A241088 * A355026 A238963 A342940 Adjacent sequences:  A074136 A074137 A074138 * A074140 A074141 A074142 KEYWORD nonn,look,tabf AUTHOR Amarnath Murthy, Aug 28 2002 EXTENSIONS More terms from Alford Arnold, Sep 17 2002 Term ordering corrected by Alois P. Heinz, Aug 21 2019 STATUS approved

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Last modified August 17 12:02 EDT 2022. Contains 356189 sequences. (Running on oeis4.)