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A074023
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Number of elements of GF(7^n) with trace 1 and subtrace 6.
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9
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OFFSET
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1,2
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COMMENTS
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Same as the number of elements of GF(7^n) with trace 2 and subtrace 3. Same as the number of elements of GF(7^n) with trace 3 and subtrace 5. Same as the number of elements of GF(7^n) with trace 4 and subtrace 5. Same as the number of elements of GF(7^n) with trace 5 and subtrace 3. Same as the number of elements of GF(7^n) with trace 6 and subtrace 6.
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LINKS
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EXAMPLE
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a(3;1,6)=6. Let GF(7^3) be defined by the field extension GF(7)[x]/( 3+b^2+b^3 ). The six elements of GF(7^3) with trace 1 and subtrace 6 are { 1+2b, 2+5b, 1+3b+b^2, 4+5b+b^2, 6+2b+6b^2, 2+4b+6b^2 }.
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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