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A068395
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a(n) = n-th prime minus its sum of digits.
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7
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0, 0, 0, 0, 9, 9, 9, 9, 18, 18, 27, 27, 36, 36, 36, 45, 45, 54, 54, 63, 63, 63, 72, 72, 81, 99, 99, 99, 99, 108, 117, 126, 126, 126, 135, 144, 144, 153, 153, 162, 162, 171, 180, 180, 180, 180, 207, 216, 216, 216, 225, 225, 234, 243, 243, 252, 252, 261, 261, 270
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refs;
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history;
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OFFSET
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1,5
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COMMENTS
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a(i) <= a(j) for i < j.
A number and the sum of its digits have the same value modulo 9. Hence all terms are divisible by 9. - Stefan Steinerberger, Apr 01 2006
Margaret Coffey (ed.) p. 440: "The sum of the digits of a two-digit prime number is subtracted from the number. Prove that the difference cannot be a prime number." Proof [p.442] "Let a and b be the tens and units digits, respectively, and let 10a+b be the prime. Subtract the sum of the digits from the number: 10a + b - (a+b) = 9a. The difference is a multiple of 9 and cannot, therefore, be prime." - Jonathan Vos Post, Feb 02 2012
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LINKS
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FORMULA
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EXAMPLE
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a(10) = 29 - (2+9) = 18.
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MATHEMATICA
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Table[Prime[n] - Sum[DigitCount[Prime[n]][[i]]*i, {i, 1, 9}], {n, 1, 60}] (* Stefan Steinerberger, Apr 01 2006 *)
#-Total[IntegerDigits[#]]&/@Prime[Range[60]] (* Harvey P. Dale, Oct 14 2014 *)
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PROG
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(Haskell)
a068395 n = a068395_list !! (n-1)
a068395_list = zipWith (-) a000040_list a007605_list
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CROSSREFS
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KEYWORD
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nonn,nice,base
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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