OFFSET
1,1
COMMENTS
a(3) = 19 because floor((3/2)^10)/floor((3/2)^3) = 19 is the smallest integer value > 1 of the form floor((3/2)^k)/floor((3/2)^3). [corrected by Michel Marcus, Jun 15 2018]
Next term is too large to include in the Data section.
LINKS
Harry J. Smith, Table of n, a(n) for n = 1..19
PROG
(PARI) a(n) = { my(r=floor((3/2)^n)); for (p=n+1, oo, my(a=floor((3/2)^p)/r); if(!frac(a), return(a)) ) } \\ Harry J. Smith, Oct 25 2009
CROSSREFS
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Dec 03 2001
STATUS
approved
