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 A065566 Numbers k such that floor((5/4)^(k+1))/floor((5/4)^k) = 5/4. 2
 7, 15, 17, 21, 25, 34, 52, 56, 59, 68, 74, 78, 99, 104, 111, 117, 118, 119, 124, 127, 129, 135, 136, 141, 145, 157, 162, 172, 179, 181, 184, 189, 190, 203, 204, 206, 209, 211, 212, 222, 226, 228, 245, 247, 250, 256, 258, 283, 291, 302, 315, 318, 327, 328, 331 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS Also, numbers k such that (5^(k+1) mod 4^(k+1))/(5^k mod 4^k)=5, or A138589(n+1)/A138589(n) = 5. (See the Mathar link in A139768.) LINKS Zak Seidov, Table of n, a(n) for n = 1..1000 FORMULA Is it true that lim_{n->infinity} a(n)/n = 6? PROG (PARI): for(n=1, 700, if(floor((5/4)^(n+1))/floor((5/4)^n)==5/4, print1(n, ", "))) (PARI) { n=0; f=5/4; for (m=1, 10^9, if ((floor(f^(m + 1))/floor(f^m)) == f, write("b065566.txt", n++, " ", m); if (n==1000, return)) ) } \\ Harry J. Smith, Oct 22 2009 CROSSREFS Cf. A065554, A138589, A139768. Sequence in context: A244536 A237054 A216848 * A329485 A154618 A275190 Adjacent sequences: A065563 A065564 A065565 * A065567 A065568 A065569 KEYWORD nonn AUTHOR Benoit Cloitre, Nov 30 2001 EXTENSIONS More terms from Jason Earls, Dec 03 2001 Edited by N. J. A. Sloane, May 24 2008 STATUS approved

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Last modified April 12 10:04 EDT 2024. Contains 371627 sequences. (Running on oeis4.)