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A065135
Numbers m such that prime(m) = pi(m)*k + 1 for some k.
2
3, 4, 6, 7, 10, 11, 14, 21, 37, 45, 47, 53, 55, 63, 75, 81, 101, 115, 121, 125, 136, 183, 209, 230, 271, 313, 319, 327, 348, 377, 399, 425, 460, 575, 581, 738, 786, 792, 850, 881, 917, 1076, 1110, 1152, 1246, 1519, 1740, 2062, 2074, 2119, 2144, 2327, 2361
OFFSET
1,1
COMMENTS
Solutions to A000040(x) mod A000720(x) = 1.
Values satisfying A065133(x) = 1.
LINKS
EXAMPLE
m = 581 is a term because prime(581) = 4211 = 106*40 + 1 = 40*pi(581) + 1.
MATHEMATICA
seq[lim_] := Module[{r = Range[2, lim], p}, p = PrimePi[r]; 1 + Position[Mod[Prime[r], p], 1] // Flatten]; seq[2400] (* Amiram Eldar, Mar 13 2025 *)
PROG
(PARI) isok(m) = if (m>1, prime(m) % primepi(m) == 1); \\ Michel Marcus, Mar 04 2022
(PARI) list(lim) = {my(k = 1); forprime(p = 3, lim, k++; if(p % primepi(k) == 1, print1(k, ", "))); } \\ Amiram Eldar, Mar 13 2025
CROSSREFS
KEYWORD
nonn
AUTHOR
Labos Elemer, Oct 15 2001
STATUS
approved