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A061295 Minimal number of steps to get from 0 to n by (a) adding 1 or (b) subtracting 1 or (c) multiplying by 3. 1
0, 1, 2, 2, 3, 4, 3, 4, 4, 3, 4, 5, 4, 5, 6, 5, 6, 5, 4, 5, 6, 5, 6, 6, 5, 6, 5, 4, 5, 6, 5, 6, 7, 6, 7, 6, 5, 6, 7, 6, 7, 8, 7, 8, 7, 6, 7, 8, 7, 8, 7, 6, 7, 6, 5, 6, 7, 6, 7, 8, 7, 8, 7, 6, 7, 8, 7, 8, 8, 7, 8, 7, 6, 7, 8, 7, 8, 7, 6, 7, 6, 5, 6, 7, 6, 7, 8, 7, 8, 7, 6, 7, 8, 7, 8, 9, 8, 9, 8, 7, 8, 9, 8, 9, 8 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
Records are a(0) = 0, a(1) = 1, a(2) = 2, a(4) = 3, a(5) = 4, a(11) = 5, a(14) = 6, a(32) = 7, a(41) = 8, a(95) = 9, a(122) = 10, a(284) = 11, a(365) = 12, a(851) = 13, a(1094) = 14, a(2552) = 15, a(3281) = 16, a(7655) = 17, a(9842) = 18, a(22964) = 19, .... - Charles R Greathouse IV, Jan 03 2017
LINKS
Charles R Greathouse IV, Table of n, a(n) for n = 0..10000
FORMULA
a(3n)=a(n)+1; a(3n+1)=a(n)+2; a(3n+2)=a(n+1)+2; a(0)=0, a(1)=1, a(2)=2.
EXAMPLE
a(20) = 6 since 20 = (0 + 1 + 1)*3*3 + 1 + 1 = ((0 + 1 + 1)*3 + 1)*3 - 1.
PROG
(PARI) steps(n, mx=3^(n-1))=my(v, s=vector(mx), u=[0], t); for(i=1, n, v=List(); for(j=1, #u, t=u[j]; if(!setsearch(u, 3*t), if(t>0 && 3*t<=mx && s[3*t]==0, s[3*t]=i); listput(v, 3*t)); if(!setsearch(u, t-1), if(t>1 && t-1<=mx && s[t-1]==0, s[t-1]=i); listput(v, t-1)); if(!setsearch(u, t+1), if(t>=0 && t+1<=mx && s[t+1]==0, s[t+1]=i); listput(v, t+1))); u=select(k->k<1 || k>mx || s[k]==i, Set(v))); for(i=1, #s, if(s[i]==0, return(concat([0], s[1..i-1])))); concat([0], s); \\ Charles R Greathouse IV, Jan 03 2017
CROSSREFS
Cf. A056792.
Sequence in context: A165359 A002308 A056796 * A081742 A127432 A199408
KEYWORD
nonn
AUTHOR
Henry Bottomley, Jun 06 2001
STATUS
approved

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Last modified April 24 13:41 EDT 2024. Contains 371957 sequences. (Running on oeis4.)