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%I #10 Aug 26 2015 01:44:28
%S 1,5,10,13,26,44,53,37,47,58,60,80,198,78,115,93,206,271,1583,144,278,
%T 235,148,185,913,366,185,215,500,251,1002,2127,8704,539,546,307,636,
%U 278,3326,290,386,665,694,313,422,364,498,455,967,748,460,731,484,1496,2005
%N Sum of continued fraction terms in Sum_{k=1..n}(1/k^2).
%e 1 + 1/2^2 + 1/3^2 = 49/36 = 1 + 1/(2 + 1/(1 + 1/(3 + 1/3))). So a(3) = 1 + 2 + 1 + 3 + 3 = 10.
%t Table[Sum[ContinuedFraction[Sum[1/i^2, {i, 1, n}]][[j]], {j, 1, Length[ContinuedFraction[Sum[1/i^2, {i, 1, n}]]]}], {n, 1, 80}] (* _Stefan Steinerberger_, Mar 24 2006 *)
%K easy,nonn
%O 1,2
%A _Leroy Quet_, May 29 2001
%E More terms from _Stefan Steinerberger_, Mar 24 2006
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